Explain a voltaic cell consists of a pb or pb2

Reference no: EM13243317

A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 degrees C. The initial concentrations of Pb2+ and Cu2+ are 5.00×10^?2 M and 1.50 M , respectively. I got the initial cell potential which is 0.51 V but now it is asking What is the cell potential when the concentration of Cu2+ has fallen to 0.250M ? Not sure how to set this problem up.

Reference no: EM13243317

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