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A student synthesized 6.895 g of barium iodate monohydrate,Ba(IO3)2.H20 by adding 30.00 ml of 5.912x10^-1 M barium nitrate Ba(NO3)2 to 50.00ml of 9.004 x10^-1 M sodium iodate,NaIO3.
a) What is the chemical equation for the reaction of barium nitrate and sodium iodate
b) Calculate the percent yield of barium iodate monohydrate the student obtained in the experiment.
Correct each of the following names. (a) SnCl4 is tin(II) chloride. (b) NaClO4 is sodium chlorite. (c) Mn2O3 is manganese(IV) oxide.
the temperature of the resulting solution rises from 25.00°C to 37.90°C. If the specific heat of the solution is 4.18 J/(g · °C), calculate ?H for the reaction, as written.
1) What volume (mL) of Hydrogen gas, saturated with water vapor, will be obtained from a 0.1138g sample of alloy which is 73.2 percent Al? (Pbar=754.3 torr, T=21.2deg C) Show your work. 2) What volume (in mL) will the dry hydrogen gas from questio..
Draw the skeletal structure of all the peptides you can make combining one of each of these amino acids. Show your products in the unionized state and omit any stereochemistry.
If a 200 mg piece of gold (density =19.32 g/cm^3) is hammered into a sheet measuring 2.3x1.0 ft, what is the average thickness of the sheet in meters?
The half life for the first order decay of 99Mo is 66.02 hours. How long will it take for a sample of 99Mo to decay
what is the molality of particles in a solution containing 25.4 g of alno33 dissolved in 530. g of water? use molar
What is the entropy of the combustion above?
The solubility of AgCl (s) in water at 25 degrees celsius is 1.33 X 10^-5 mol/L and its change in enthalpy of solution is 65.7 kJ/mol. What is its solubility at 54.8 degrees celsius
The base peak in the mass spec of phenylacetic acid indicated that the compound lost a fragemnt that has an m/z= 17. This fragmentation corresponds to the loss of a(n)
fifty grams of nh4cl was dissolved in 100 ml of water. the calculated delta heat for the reaction was 15.2 kj. what is
Titration will require more moles of base than acid to reach the equivalence point. E. titration will require more moles of acid than base to reach the equivalence point.
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