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A 136.6 mg sample of a crushed Vitamin C tablet was dissolved in 40 mL of H2SO4 and 20 mL of water. 2 grams of KI and 25.00 mL of 0.0155 M KIO3 solution was added, and the mixture was titrated to a starch endpoint. The titration required 20.34 mL of 0.0491 M thiosulfate solution.Calculate the weight percent of ascorbic acid in a tablet of Vitamin C
What volume of hydrogen is necessary to react with five liters of nitrogen to produce ammonia?
A 1.17-g sample of a mixture of cyclohexane (C6H12) and naphthalene (C10H8) is dissolved in 17.9 g of benzene (C6H6). The freezing point of the solution is 2.2°C. Calculate the mass percent of the mixture.
A galvanic (voltaic) cell consists of an electrode composed of chromium in a 1.0M Chromium(II) ion solution and another electrode composed of silver in a 1.0M silver ion solution, connected by a salt bridge.
Using the values for the resonance energies of benzene and naphthalene given above, explain why Diels-Alder reactions of anthracene take place at the center ring, not one of the end rings.
The solubility product of PbBr2 is 8.9x10^-6. Determine the molar solubility a) in pure water, b) in 0.20M KBr solution, c) in 0.20M Pb(NO3)2 solution.
The sodium hypochlorite reacts with hydrochloric acid producing chlorine gas. What is the reducing agent in this reaction
A mixture of 4.50 g of He, 12.0 g of Ne, and 29.0 g of Kr is placed in a cylinder at STP. Calculate the partial pressure of each gas.
Ascorbic acid is titrated with 23.1 mL of 0.5 M KIO3. How many moles of ascorbic acid are present?
The endpoint of a titration is not exactly the same as an equivalence point. Why does the titration still work to use the endpoint
You prepared a 0.250 M solution by diluting 8.45(+-0.04)mL of 28.0(+-0.5)mL wt.%NH3 (density=0.899(+-0.003)g/mL up to 500.0(+-0.2)mL. Find the uncertainty in 0.250 M.
What volume in liters of gaseous hydrogen chloride can be prepared from 40.0 liters of hydrogen with excess of chlorine. All volumes are measured at STP.
We did a lab where we added vanillin, acetic acid, potassium bromate and hydrobromic acid together. The product we got was analyzed to be 5-bromovanillin.
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