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We're not told that the top 1000 would be the majority. IF that is true then the sample might be a good indicator for the company. However, if it is not true then it's probably not representative of all the customers and could lead to strange projections.
One question that I have is: Will these sample statistics accurately estimate the purchasing habits of all our customers? Can you share some of your thoughts on that question? Why or why not?
the null hypothesis is to be tested at 95% confidence. Determine the critical value(s) for this test.
A researcher wants to determine a 95% confidence interval for the mean number of hours that UMKC students spend doing homework per week.
A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought in to the time repairs are completed. A random sample of 12 repair records showed the following repair (in days)
Using the telephone numbers listed in your local directory as your population, randomly obtain 20 samples of size 3. From each telephone number identified as a source, take the fourth, fifth, and sixth digits.
What will be critical value of chi-square if test is to be performed at 0.025 level? At the 0.05 level?
A film alliance used a random sample of 50 U.S. citizens to estimate that the typical American spent 78 hours watching videos and DVDs last year. The standard deviation of this sample was 9 hours.
Assuming that the Poisson distribution is a plausible model in describing variability of asbestos fiber counts in filters; derive a 95% confidence interval indicating the variability in the average number in asbestos fibers.
Find the average age at which people will experience their first cardiac incident, given that 17% of all initial cardiac incident victims are younger than 50. Please, interpret the result.
Is it reasonable typical worker does not miss any days during a pay period?
Office Visits what is the age distribution of patients who make office visits to a doctor or nurse?
Twenty subscribers were surveyed, it found that the annual health insurance premiums for a family with coverage through an employer averaged $10,979.00. The standard deviation of the sample was $1000.00.
a) Find the 95% confidence interval for the population mean based on the 37 patients who remain after you drop the outlier. b) Compare your interval in (a) with your interval from Exercise 18.32. What is the most important effect of removing the ou..
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