Solution-Effective cross-sectional area of the object

Effective cross-sectional area of the object

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Reference no: EM132029835

Shown to the right is a truncated cone of length L cm traveling through a fluid at a speed of 8.80 m/s. The narrow end of the cylinder has a diameter of 2.12 cm, whereas the wider end has a diameter of 3.22 cm. The drag force acting on the cylinder is 29.6 newtons.

The drag force Fd acting on an object passing through a fluid is given by where A is the effective cross-sectional area of the object, Γ (the Greek letter "gamma") is the drag coefficient, ρ is the density of the fluid, and v is the speed of the object. Calculate the drag coefficient Γ of the object if the fluid is water of density 1000.00 kg/m3

Reference no: EM132029835

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Effective cross-sectional area of the object

Reference no: EM132029835

Reference no: EM132029835

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