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The new director of special programs in XYZ Corporation felt the customers were waiting too long to receive and complete forms needed to enroll in special programs. After collecting some data, Ms. Jones determined the mean wait time was 28 minutes. She felt this time period was excessive and she instituted new procedures to streamline the process. One month later, a sample of 127 customers was selected. The mean wait time recorded was 26.9 minutes and the standard deviation of the sampling was 8 minutes. Using the .02 level of significance, conduct a five-step hypothesis testing procedure to determine if the new processes significantly reduced the wait time.
Perform a hypothesis test with significance level 5%. Show all work, and clearly state your conclusion.
Calculate the Coefficient of Skewness and the Coefficient of Variation for time spent working on QM.
Recognize strategies that were utilized to control for nuisance variables and minimize threats to valid inference making.
Calculate a 95% confidence interval for the population mean, based on the sample 10, 12, 13, 14, 15, 16, and 49.
At the .05 significance level, is the number of units produced on the afternoon shift larger?
Discuss possible study designs. Which of the designs would we use to test our research hypothesis?
What factors might cause the company to order a larger or smaller amount than the EOQ?
In textile industry, a manufacturer is interested in the number of blemishes or flaws occurring in each 100 feet of material. Of the following probability distributions, the one that most applies to this situation is the.
A professor of math refutes the claim that the average student spends 3 hours studying for the midterm exam. Which hypothesis is used to test the claim?
Probability using normal distribution.Sampling distributions. Given a normal distribution with μ = 50 and standard deviation σ = 9, if a sample of n = 100 is selected.
The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0. Assume 36 golfers played the course today. Find the probability that the average score of the 36 golfers exceeded 71.
Which of the following is true about the expected value of perfect information. It is the amount you would pay for any sample study.
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