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Determine the quantity of pure

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Reference no: EM131926264

Determine the quantity (g) of pure CaCl2 in 7.5 g of CaCl2•9H2O.

7.5g CaCl2 * 9H2O * 1molecacl2 * 9h2o/ 273.12 grams  = .027moles

0.27moles CaCl2 *9H20   * 110.98g cacl2/ 1 mole CaCl2= 2.9964 grams, with correct Sig Fig, 2.9 Grams wondering if someone can help double check my answer here, a little unsure of my calculations.

Reference no: EM131926264

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