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1. Write the chemical equation for water.
2. Draw a stick model of a water molecule.
3. Sketch a space filling model of a water molecule, show polarity by labeling positive and negatively charged regions of the molecule.
At 25 c and 1.0 atm, 0.25 g of a gas dissolves in 1.00 L of water. What mass of the gas dissolves in 1.00 L of water at 25 c and 3.0 atm?
2Al + 6HBr = 2AlBr3 + 3H2 If .427 g of Al reacts calculate the amount of hydrogen produced
Use the collision theory to calculate the theoretical value of the second-order rate constant (in m3 mol-1 s-1) for the gas-phase reaction D2 + Br2 = 2 DBr at 450 K assuming that it is elementary bimolecular. The collision cross-section for this r..
When benzoic acid is partitioned between diethyl ether and queous sodium hydroxide solution and the aqueous layer is separated, acidification of the aqueous solution yields a precipitate.
The molality of sodium nitrate solution us 1.44m. What is mole fraction of NaNo3. The molar mass of NaNo3 is 85.06g/mol
In a laboratory investigation involving a neutralization reaction, a scientist adds potassium hydroxide to nitric acid (balanced reaction following):
the product for the following reaction between THF and excess HI, and provided a detailed step-bystep mechanism for its formation, using the curved arrow formalism
How many Joules of energy are stored in 1 pound (454 g) of sucrose? (Assume: Pressure = 1 atm, Temperature = 25°C; the respective ?Hf° for the reactants and products can be found in the thermodynamic table linked above. Show your calculation
What alkyne (or diyne) yields the following oxidative cleavage products. CO2+CH3(CH2)8CO2H
Which is the limiting reagent in the reaction between Copper sulfate pentahydrate and ammonia?
the concentration of co2 in the soda is 0.14M. find the concentration of CO2 in the soda after the bottle is opened, and equilibrates at a partial pressure of 3.0 X 10^-4 atm. The henry's law constant is 3.4 X 10^-2 mol/L atm.
when atoms lose more than one electron, the ionization energy to remove the second electron is always more than the ionization energy to remove the first.
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