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1. Explain the purpose of heating the crucible and the sample to "constant mass" this is done in step 11.
2. why should you not weigh the crucible while it is hot? (hint: think about what happens to air when it is heated.)
3. Explain how the calculated formula of the hydrate would be changed if water from the air is absorbed by the hot dry sample as it cools.
Acetic anhydride, like any anhydride, reacts with water to form a carboxylic acid. How is it then possible to carry out an acetylation in aqueous solution?
how many milliliters of 0.0850 m NaOH are required to titrate each of the following solutions a) 40.0 ml of 0.0900 m HNO3 B)35.0 ml of 0.080 m HC2H3O2 c) 50.0 ml of a solution that contains 1.85 g of HCl per liter.
Determine what mass of sulphuric acid would be needed to mix with 0.75 mol of sodium hydroxide(NaOH)?
Calculate the number of moles of O2 required to react with phosphorus to produce 5.50 g of P4O6. (Molecular mass P4O6 = 219.9 g/mol.)
Solid silicon and solid magnesium chloride form when silicon trichloride gas reacts with magnesium metal. Write a word equation and an unbalanced formula equation.
Part A. At 25°C, another student has the following data for the aluminum cylinder. The uncertainty in mA, mB, and mcyl is 0.001 g.
At 25 0C the density of a 50 % (by mass) ethanol/water solution is 0.914 g/cc. Given that the partial molar volume of water in the solution is 17.4 cc/mol.
At equilibrium a 2L vessel contains .410 mol of H2, .130mol of Br2, and 36.0 mol of HBr. What is the equilibrium constant for the reaction at this temperature?
The hydrogen carbonate ion can act as both an acid and a base. Write out two equations which demonstrate this and calculate (or look up) the equilibrium constants for both expressions
Briefly comment on the differences in these two concentrations. calculate the [OH] in a 1.0M NaOH solution and in a buffer containing 1.0 M NH3 and 1.0 M NH4Cl.
Which step is the rate determining step on a reaction?
The first-order decomposition of phosphene to phosphorus and hydrogen 4PH3(g) → P4(g) + 6H2(g)
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