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Problem- Show calculations for how you will prepare 250 mL of 0.1 M AgNO3 solution from solid AgNO3 and water. Give the reagent amounts and units.
.1M x .250l = .025 mols
169.872 g mol
.025/169.872
0.00001177357
1x10-5 g ?
I have read my textbook in addition I at a halt don't understand thus please provide me a very strong and simple answer?
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