Reference no: EM131268784

Project - Simple Vending Machine FSM

Objective

The objective of this project is to implement, in VHDL, a Finite State Machine, using the main clock of the Digilent Board to drive the state machine. The finite state machine will control a vending machine to dispense soda cans that are worth 50¢. Since this project will require several modules, consider using a mixed schematic/VHDL design, where you can use a schematic as the top level module, and have each sub-module defined in VHDL.

The vending machine has three inputs:

QUARTER: a signal that goes high and then low when a quarter has been deposited

CLOCK: a clock that will drive the FSM

RESET: a signal that will reset the FSM to its initial state

The vending machine has two outputs:

COUNT: a signal that goes high when a single quarter has been accepted. This signal should remain high for one clock cycle.

DISPENSE: a signal that goes high when the soda has been dispensed

Part I

Create a clock divider module to divide the master clock (at 50MHz) to a 1Hz clock. You may also need to create a switch debouncer for the QUARTER input to avoid confusing the FSM.

Part 2

Create your state diagram that you will use to implement the FSM VHDL module. The vending machine behaves as follows:

· If the RESET input is asserted, the FSM will go to the initialization state (S_init) immediately. All of the outputs should be zero in this state.

· From the initialization state S_init, the FSM will unconditionally go to the wait state (S_wait)

· From the wait state S_wait, the FSM waits for the QUARTER switch to be activated.

· If QUARTER is asserted, the FSM goes to state S_Q1. In this state, the COUNT output is set to 1, indicating that a quarter has been accepted. The FSM will stay in this state until the QUARTER input is de-asserted. When this occurs, the FSM goes to state S_QW1, then unconditionally to state S_QW2 and the COUNT output is set to 0. The FSM waits for the QUARTER switch to be activated.

· If QUARTER is asserted while the FSM is in S_QW2, then the state machine goes to state S_Q2. In this state, the COUNT output is again set to 1. The FSM will stay in this state until the QUARTER input is de-asserted. When this occurs, the FSM goes to S_QW3, and then unconditionally to state S_dispense, the COUNT output is set to 0, and the DISPENSE output is set to 1.

· From state S_dispense, the FSM unconditionally goes to state S_init.

Your VHDL MUST have two process: a next-state process to determine the change of states, and a output_logic process, to determine the outputs. Please include a state diagram and test bench outputs in your report. Put all VHDL code, including test benches in the appendix.