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A study is run comparing HDL cholesterol levels between men who exercise regularly and those who do not. The data are shown below.
Regular Exercise N Mean Std DevYes 35 48.5 12.5No 120 56.9 11.9
Generate a 95% confidence interval for the difference in mean HDL levels between men when exercise regularly and those who do not.
A clinical trial is run to assess the effects of different forms of regular exercise on HDL levels in persons between the ages of 18 and 29. Participants in the study are randomly assigned to one of three exercise groups - Weight training, Aerobic exercise or Stretching/Yoga - and instructed to follow the program for 8 weeks. Their HDL levels are measured after 8 weeks and are summarized below.
Exercise Group N Mean Std DevWeight Training 20 49.7 10.2Aerobic Exercise 20 43.1 11.1Stretching/Yoga 20 57.0 12.5
Is there a significant difference in mean HDL levels among the exercise groups? Run the test at a 5% level of significance. HINT: SSwithin = 21,860.
The travel time for a college student traveling between her home and her college is uniformly distributed between 40 and 90 minutes.
A medical school claims that more than 32% of its students plan to go into general practice. It is found that among a random sample of 130 students, 46 of them plan to go into general practice.
Over the last year the absentee rate at a large corporation averaged 8.2 days absent with a standard deviation of 6 days. One department with 40 employees had an absentee rate of 12 days per employee.
Based on the information in (a), find a one-sided lower 90% confidence limit for m. Also, find a one-sided upper 90% confidence limit for m.
Assuming that n = 6 for both samples, calculate each of the sample variances, then calculate the pooled variance. Because the samples are the same size, you should find that the pooled variance is exactly halfway between the two sample variances.
In a clinical study of an allergy drug, 112 of the 210 subjects reported experiencing significant relief from their symptoms. At the 0.01 significance level,
In a random sample of 225 students at a university, 180 stated that they were nonsmokers. Based on this sample, compute a 95% confidence interval for the proportion of all students at the university who are nonsmokers.
Find the standardized test statistic to test the claim that mean1 = mean 2. Two samples are randomlu selected from each population. The sample statistics are given below.
Produce the summary output and give the estimated equation for your chosen model and find a suitable regression model to predict y2 using x2 as an explanatory variable. Comment on the output used and justify your choice of model.
Analyze the data using linear contrasts to make the following comparisons:
Do the confidence interval limits contain 98.6F? What does the sample suggest about the use of 98.6F as the mean body temp.
If the limits of the confidence interval of the difference between the means of two normally distributed populations were 3.5 and 5.5 at the 95% confidence level, then we can conclude that we are 95% certain that there is a significant difference ..
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