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Joan's nursery specializes in custom-designed landscaping for residential areas. the estimated labour cost associated with a particular landscaping proposal is based on the number of plantings of trees,shrubs and so on to be used for the project. for cost-estimated purposes, managers use two hours of labour time for the planting of a medium sized tree. actual times from a sample of ten plantings during the past month follow (times in hours)
1.7 1.5 2.6 2.22.4 2.32.6 3.0 1.42.3
with a 0.05 level of significance, test to see whether the mean tree-planting time differs from two hours.
1) state the null and alternative hypothesis
2) compute the sample mean
3) compute the sample standard deviation
4) compute the sample (test) statistic
5) formulate the decision rule
6) what is your conclusion
We have been informed that the stock has gone up 20%. What is the probability of a rise or fall in the GDP?
What proportion of sample means would be between 1.31 and 1.33 inches?
The random number generator on calculators randomly generates a number between 0 and 1. The random variable X, the number generated, follows a Uniform Probability Distribution. What is the probability of generating a number between 0 and 0.2?
The following data resulted from a taste test of two different chocolate bars. The first number is a rating of the taste, which could range from 0 to 5, with a 5 indicating the person liked the taste which could range from 0 to 5
The number of items rejected daily by the manufacturer because of defects for last 30 days are:
A large internet retailer is studying the lead time (elapsed time between the time when the order is placed and the time it is filed). The table below gives the lead times (in days) for a random sample of recent orders.
The theory underlying inferential statistics and other theoretical aspects are subjects we do not often consciously think about in our daily activities.
Determine the area under the standard normal curve that lies: (a) to the left of Z = -2.31 (b) to the right of Z = -1.47 (c) between Z = -2.31 and Z = -1.47 (d) between Z = 1.47 and Z = 2.31
What is your conclusion regarding null hypothesis?
Exam is given to 20 randomly chosen students and their average length of t time needed to finish exam was 54 minutes with standard deviation of 5.99 minutes. Test instructor's claim at the 0.05 level of significance.
Would you be willing to provide an example of both methods (step by step) described in your document for determining the forecast based upon the two different methods. Maybe just for one single city.
What is the likelihood the sample mean is greater than $22.50 but less than $25.00?
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