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Q1) Shaver Manufacturing, Inc., provides dental insurance to its employees. A current study by human resource director illustrates annual cost per employee per year followed normal probability distribution, with mean of $1,280 and a standard deviation of $420 per year.
a) Determine fraction of employees cost more than $1,500 per year for dental expenses?
b) Compute fraction of the employees cost between $1,500 and $2,000 per year?
c) Evaluate percent that didn't have any dental expense.
d) Determine the cost for 10 percent of employees who incurred highest dental expense?
Which of the following events are disjoint and What proportion of the females rated their intelligence less than 7.
In a regression model involving 30 observations, the following estimated regression equation was obtained:
Karefree State University has an enrollment of 18,000. Researchers took a sample of 900 and found 477 students wanted a Field Hockey team. Construct the 95% and 99% Interval estimates for the population proportion.
The average number of days absent per student per year at West Valley School is 17 days with a standard deviation of 4 days. How many standard deviations from the mean is 6 absent days?
Analyze the data using linear contrasts to make the following comparisons:
A survey taken in a restaurant shows the following number of cups of coffee consumed with each meal. Construct an ungrouped frequency distribution.
The standard deviation of the population of adult female height scores is 3 inches. A random sample of 50 women yields a mean height of 64 inches. Calculate the standard error of the mean.
Using the .05 level of significance: a) Is there a difference among types of gasoline? b) Is there a difference in the cars?
Let be the average of the pay you receive for the first and second week. Find the sampling distribution
Research question: Are mean crash damages same for these 3 vehicles? Crash1 Crash Damage ($).
A restaurant monitors its customer's complaints, With information, which of the following is a Pareto chart of the data?
To test whether there is any association between two variables using Chi-Square test for independence.
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