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There are 1 x 1079 electrons in the universe. The following numbers may be useful: me = 9.11 x 10-31kg, mp = 1.67 x 10-27kg, qp = -qe = 1.6 x 10-19C. (a) Compute the total charge of the electrons in the universe.
A hollow sphere of radius R has a potential on its surface specified by the function V(R,θ) = Vocos2θ. Find the electric potential inside and outside the sphere
A bowling ball encounters a 0.76 m vertical rise on the way back to the ball rack, as the drawing illustrates. find the translational speed at the top
A 3500 resistor and a 1.1 µF capacitor are connected in series across a generator (60.0 Hz, 120 V rms). Determine the average power dissipated in the circuit
A 1.0-kg block is pushed up a rough 22o inclined plane with a force of 7.0 N acting parallel to the incline. The acceleration of the block is 1.4 m/s2 up the incline. Decide the magnitude of the force of friction acting on the block.
An ultraviolet lamp emits light of wavelength 400 nm at the rate of 430 W. An infrared lamp emits light of wavelength 700 nm, also at the rate of 365 W. Which lamp emits photons at the greater rate
Vector A has a magnitude of 5.0m and a direction of 60 degrees; the vector B has a magnitude of 4.0 and a direction of 20 degree from positive x-axis. What is the direction of the resultant vector
An object accelerates from 19 m/s to 50 m/s in 15 seconds. What is the objects acceleration in m/s2
a mass of 0.30 kg is attached to a spring and is set into vibration with a period of 0.24s. what is the spring
a tennis player standing 12.6 m from the net hits the ball at 3.27deg above the horizontal. to clear the net the ball
A tightrope walker is practicing. She is balanced on a rope at the exact midpoint of the rope. The tension in the rope is 4000 N, and the mass of the tightrope walker is 56 kg. Consider the left side of the rope. What angle with the horizontal does i..
Sketch a graph with distance on x axis and acceleration on y axis showing what happens to one object after string is cut. Explain
Assume that none of the alpha particles bounced back from the sheet, meaning that the alpha particles either were captured by the shielding or penetrated completely through the shielding.
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