Compute the ph of benzoic acid is dissolved in water

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Calculate the pH of Benzoic acid if 0.0458 M is dissolved in water ( Ka = 6.40 x 10^-5) C6H5CO2H + H2O = (H3O+) + C6H5CO2 ^-1

What is the Kb for the above conjugate base (C6H5CO2^-1) that produces OH^-1 in water? C6H5CO2^-1 + H2O = C6H5CO2H + OH^-1

Reference no: EM13182181

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