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The human eye is able to detect as little as 2.35 x 10 ^-18 J of green light of wavelength 510 nm. Calculate the minimum number of photons of green light that can be detected by the human eye.
Based on the half-reactions and their respective standard reduction potentials below, which addition to an aqueous solution containing Fe(NO3)2 will result in a reaction under standard-state conditions?
A solution is prepared by dissolving 0.60g of nicotine in water to make 12mL of solution. The osmotic pressure of the solution is 7.55atm at 25 degrees C
A buffer having equal amounts of a weak acid and its conjugate base has a pH =4.4. A small amount of sodium hydroxide was combined to this buffer solution .
How many grams of dry NH4Cl need to be added to 1.80 L of a 0.800 solution of ammonia, NH3, to prepare a buffer solution that has a Kb of 8.87? for ammonia is 1.8E-5.
How much potassium nitrate has to dissolve in water to absorb 114 kJ of heat?
Write out the reaction mechanism for the side reaction of acetic anhydride with 85% phosphoric acid to make two
Super-green is an indicator with a Ka of 1.6 × 10-7. The acid form is yellow and the base form is blue. Awesome-orange is an indicator with a Ka of 5.0 × 10-5.
A gas has a volume of 150 ml when its pressure is 0.947 atm. What will the volume of the gas be at a pressure of .987 atm, if the temperature remains constant
WHich of the following will act as a lewis acid? (please explain why as I need to understand the concept)
What volume of 0.0100 M KMnO4 solution is required to oxidize 42.5 mL of 0.0100 M FeSO4 sulfuric acid solution?MnO4- + 8H+ + 5Fe2+ ® Mn2+ + 5Fe3+ + 4H2O
Calculate the energy change for the reaction K(g) + I(g) → K+(g) + I- (g) given the following ionization energy (IE) and electron affinity (EA) values. IE K = 419 kJ/mol, IE I = 1010 kJ/mol; EA K = 48 kJ/mol. EA I= 295 kJ/mol
Using the volumes of sodium thiosulfate solution you just entered and the molarity of the potassium iodate primary standard solution, calculate the molarity of the sodium thiosulfate secondary standard solution for each trial.
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