Compute the amount of excess reactant

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MnO2(s) + 4HCl(aq) ? MnCl2(aq) + Cl2(g) + 2H2O(l) In the above reaction 2.43 g of MnO2 and 5.80 g of HCl react to form chlorine gas. a. How many moles of Cl2 can be produced from the given mass of MnO2? b. How many moles of Cl2 can be produced from the given mass of HCl? c. Which reactant is the limiting reactant? d. What is the maximum amount of Cl2 that can be produced by this reaction? e. Calculate the amount of excess reactant.

Reference no: EM13332079

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