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When ethylamine, a weak base (Kb=4.3E-4), reacts with the formic acid, a weak acid (Ka=1.8E-4), the following reaction takes place:
\(CH_{3}CH_{2}NH_{2}(aq) + HCOOH(aq)<-->CH_{3}CH_{2}NH_{3}^{+}(aq)+HCOO^{-}(aq)\)
Calculate K for this reaction.
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