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1. A standardized solution of sodium hydroxide at 0.239 M was used to titrate an unknown acid comprising 3 acid hydrogen ions. Knowing that 32.4 mL of base were required to reach the end point with a sample of 1.95 g of acid, calculate the molar mass of the acid.
H3A + 3NaOH = Na3A + 3H2O
1 mol 3 mol 1 mol 3 mol
Number of moles of NaOH = .0324 L x .239 M = .00774 mol/L
Molar Ratio: 1:3
Number of moles of H3A = .00774 mol x 1/3 = .00258 mol
Molar mass of H3A = 1.95 g / .00258 mol = 755.8 g/mol
The molar mass of the acid is 756 g/mol (3 significant numbers)
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