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A sample of a substance with the empirical formula XCl3 weighs 0.5292 g. When it is dissolved in water and all its chlorine is converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found to be 1.4026 g. The chemical reaction is
XCl3 + 3 AgNO33AgCl + X(NO3)3
(a) Calculate the formula mass of XCl3.
Formula mass XCl3 = g mol-1
(b) Calculate the atomic mass of X.
Atomic mass X = g mol-1
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