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Calculate ?H for the reaction 2C(s) + H2(g) ? C2H2(g) given the following reactions and their respective enthalpy changes
1. C2H2(g) + 5/2 O2(g) ? 2CO2(g) + H2O(l) ?H= ?1299.6 kJ
2. C(s) + O2(g) ? CO2 (g) ?H= ?393.5 kJ
3. H2(g) + ½ O2(g) ? H2O(l) ?H= ?285.8 kJ
Acetylene gas (C2H2) is produced as a result of the following reaction. CaC2(s)+2H2O(l) = C2H2(g)+Ca(OH)2(aq) . If 32.0 g of CaC2 are consumed in this reaction, how many moles of H2O are needed?
A 25.0 mL sample of a 0.115 M solution of acetic acid is titrated with a 0.144 M solution of NaOH. Calculate the pH of the titration mixture after 10.0, 20.0, and 30.0 mL of base have been added.
A 4.50-g sample of liquid water at 25.0 C is heated by the addition of 133 J of energy. The final temperature of the water is __________ °C. The specific heat capacity of liquid water is 4.18 J/gK.
what is the major type of force that must be overcome to allow each of process below
the specific heat of ethylene glycol is 2.42 J/g-K. How many J of heat are needed to raise the temperature of 62.0 g of ethylene glycol from 13.1 C to 40.5 C ?
An electrophilic addition is? Answer . a) An addition to an alkene initiated by a nucleophilic attack. b) An addition to an alkene initiated by an electrophilic attack
How many grams of acetylene are produced by adding water to 5.0 grams CaC2
An auto mechanic spills 90. mL of 2.6 M H2SO4 solution from a rebuilt auto battery. How many milliliters of 2.5 M NaHCO3 must be poured on the spill to react completely with the sulfuric acid
What is the energy per photon of the lowest frequency of electromagnetic radiation that can be used to observe a gold atom with a diameter of 280 picometers.
lots of space between gas particles B. little to no space between gas particles C. nothing about the space between gas particles can be inferred.
Calculate the mass, in grams for a gold sample that absorbs 225 J to change its temperature from 15 Celsius to 47 degrees celsius.
Estimate the pH, and the concentrations of all species in a 0.300 M phosphoric acid solution. pKa1: 2.16 pKa2: 7.21 pKa3: 12.32 Hint: Convert the pKa values to Ka values
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