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Question- When 1.045 g of K2O is added to 50.0 mL of water at 25 degrees celcius in a calorimeter, the temperature of the water increases to 41.5 degees C.
Assuming that the specific heat of the solution is 4.18 J/(g*C) and that the calorimeter itself absorbs a negligible amount of heat, calculate delta H in kilojoules for the reaction
K2O(s) + H2O(l) --> 2KOH(aq)
I need proficient help to working out this problem
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