### C++ programs that compute the agreement for two vectors

Assignment Help C/C++ Programming
##### Reference no: EM13300279

Programming Assignment

The agreement for two binary vectors A and B, each of size n+1, is defined as the following:
int sum=0; for (int i=0; i<=n; i++) if (A[i]==B[i]==1) sum++; (Calculation 1)

In this assignment, you write C++ programs that compute the agreement for two given vectors (see Calculation 1 above). In these programs, in vectors A and B only nonzero elements (elements that are 1) are stored. We give you a function that generates input for a test case for your programs. Both correctness and efficiency of your programs are important.

Please see Attachment #1 for this assignment. However, you implement a linked list version of the program started in Attachment #1, which uses arrays. That is, instead of an array, you use linked lists to store the non-zero elements of the vectors. This involves changing struct definition to include a link, and writing a new agreement() function. Keep the same input vectors, but you need to write a new generate_row_and_col() function to create linked lists.

YOUR WORK IS DUE 11:59PM ON THURSDAY, SEP. 11.

/* ATTACHMENT 1: */

#include <stdio.h>
#include <iostream.h>

/*
For Assignment #2
You are asked to write a function that calculates the agreement for two vectors, a row and a column

Normally this agreement can be calculated as follows:
int sum=0; for (i=0;i<=n; i++) if (A[i]==B[i]==1) sum++;
(Calculation 1)
But, you will need to do it differently since zeros are not stored in vectors

function generate_row_and_col() below is provided only for testing. Your function should not be designed for a fixed pair of row or column vectors;
row is a row vector of size at most n,
col is a (column) vector of size at most n,

each of these vectors stores only 1's

here we use an array to store the indices at which the element is 1

e.g. for row vector [0,0,1,0,0,1,0], which has 1's at indices 2, and 5, respectively
row[0]=2;
row[1]=5;
row[2]=-1 (-1 in x marks the end of non-zero elements in row)

Please note that all other elements (not stored in row) are zeros

Similarly let col be the following vector [0,0,0,0,0,1,0], then
col[0]=5;
col[1]=-1;

For this pair of row and col, the agreement is 1, because row[1]=col[0]=5, and all other terms in Calculation 1 (see the top of the page) are zeros
*/

static const int n=1000; /* vector size limit */

struct element {
int x; /* original index of non-zero array element */
int val ; /* integer non-zero value at index x */
} ;

int row[n] ;
int col[n] ;

int i;

void generate_row_and_col() {
for (i=1; i<n/4; i++) row[i]=4*i;
row[0]=1;
row[n/4]=-1;
for (i=1; i<n/5; i++) col[i]=5*i;
col[0]=1;
col[n/5]=-1;
}

int agreement()
{
/* calculate the agreement for row and col;
output the result
*/

}

int main()
{
generate_row_and_col() ;

agreement();
return 0;}

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