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As part of a dietary-instruction program, ten 25-34-year-old males adopted a vegetarian diet for 1 month. While on the diet, the average daily intake of linoleic acid was 13 g with standard deviation = 4 g. If the average daily intake among 25-34-year-old males in the general population is 15 g, then, using a significance level of .05, test the hypothesis that the intake of linoleic acid in this group is lower than that of the general population. Also, compute a p-value for the hypothesis test.
What happens to the confidence interval when we go from a 95% confidence level to a 99% confidence level? Is this desirable? When would we want to use a 99% confidence interval?
What percent of the Fords traveled 62.000 miles or less during the year?
Determine the test value? Use α = 0.05. (Use the variances unequal formula).
Calculate the sample mean and sample standard deviation.
To what probabilities do each of the following sigma levels correspond to, based on a standard normal curve: 3 sigma, 4sigma, 5 sigma, and 6 sigma? (Hint: Use the NORMSDIST function in Excel.
The data consists of random sample of 30 households from the 2007 American Community Survey. Construct a frequency distribution and a histogram for each data set.
Mention all samples of size 3, and compute the mean of each sample. Compute the mean of the distribution of sample means and the population mean.
What is the probability she received 5 or more email during the same period?
Utlizing binomial approximation to normal finding the normal model. A grower claims that only 13 percent of the strawberries he grows are unsatisfactory.
If we know that 20 people will attend, what price should be charged per person to break even?
What is your initial perception of this information? What are other ways, beyond looking at the p-value alone, you could use to try to interpret what this outcome of r(2398) = -.21 tells us about the relationship between length of time taking drug..
You find that a random sample of five microwave ovens has a mean repair cost of $75 and a standard deviation of $12.50. At α = 0.01, do you have enough evidence to support the repairer's claim?
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