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Suppose that the exact values of the data x1, ..., x50 from an exponential distribution EXP(theta) are unknown, but it is known that 40 of the 50 measurements are larger than t.
a) Find an approximate one-sided lower 95% confidence limit for P(X>t) based on this information.
b) Note that under the exponential assumption, P(X>t) = exp(-t/theta). If t=5, use the result from (a) to find an approximate one-sided lower 95% confidence limit for theta.
After performing a two sample t-test, you see a p-value of 0.0355. Of the following, which is the appropriate conclusion?
Using 5% level of significance, is there any difference in proportion of guests who would select the two resorts? What is your conclusion?
At.05 level of significance test to find out if number of breakdowns is independent of shift.
A biologist has found the average weight of 12 randomly selected mud turtles to be 8.7 lb with standard deviation 3.6 lb. find a 90% confidence interval for the population mean weight of all such turtles.
Use the relative frequency approach to construct a probability distribution for the number of tests taken.
The hypothesis is to be tested at the 5% level of significance. The critical value from the table equals:
In a group of seven adult friends, what is the probability that: a) no one has done a one-time fling?
The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages.
If you did not know anything about standard deviation of population from which sample was taken, find out the 95% confidence interval for mean test score.
Use a calculator or appropriate computer software to verify that, for the preceding data, xbar = 5.1.
From the given research, compare the major players better at batting than 20 years ago using five step hypothesis.
Consider the following estimated regression equation, based on 10 observations.
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