Solution-Ammonia in excess oxygen, You have 8 g of methane

Ammonia in excess oxygen

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Reference no: EM131824196

1. Methane (CH₄), ammonia (NH₃), and oxygen (O₂) can react to form hydrogen cyanide (HCN) and water according to this equation:

CH₄ + NH₃ + O₂ à HCN + H₂O

You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer the following questions:

What is the balanced equation for this reaction?
Which reagent is limiting? Explain why.
How many grams of hydrogen cyanide will be formed? Show your work.

Answer:

Score

2. What is the electron configuration of an electrically neutral atom of sodium?

What is the electron configuration of an electrically neutral atom of neon?

What is the electron configuration of an electrically neutral atom of oxygen?

Answer:

Score

3. Given the chemical formulas of the following compounds, name each compound and state the rules you used to determine each name.

RbF
CuO
(NH₄)₂C₂O₄

(Note: C₂O₄^- is called oxalate.)

Answer:

Reference no: EM131824196

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Ammonia in excess oxygen : You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer the following questions:

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Ammonia in excess oxygen

Reference no: EM131824196

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