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If the probability is 0.75 that a person will believe a rumor about the transgressions of a certain politician, find the probabilities that
(a) the eighth person to hear the rumor will be the fifth to believe it;
(b) the fifteenth person to hear the rumor will be the tenth to believe it.
given the following table of payoffs use sensitivity analysis to determine at what probability or more you would select
Sample of newspaper readers was asked to report which newspaper they read and to point to whether they were blue-collar worker, white-collar workerNewspaper reader is selected at random. Determine the probability that person selected.
In Problem 10.12.1, we found that passing a stationary white noise process through an integrator produced a nonstationary output process Y(t). Does this example violate Theorem 11.2?
The probabilities .9 and .1 respectively. Give the probability distribution for daily sales. Find the mean and standard deviation of the daily sales.
Find the probability that in a sample of 10 tools chosen at random exactly 2 will be defective by using (a) the binomial distribution and (b) the Poisson approximation to the binomial distribution.
in a sample of 800 people 326 of them were found to have frequent headaches. what is the sample proportion of people
Julia's cost for the soft drinks are 55 cents, and she sells them for two dollars. She can expect to sell just as many soft drinks as all food items combined.
Find the amount credited and the outstanding balance on an invoice dated August 19 if a partial payment of $500 is paid on August 25 and has terms of 3/10, 1/15, n/30. The amount of the invoice is $826
Assume that a 95% confidence interval for the mean is 14.5
A 95% confidence interval for the mean of a normal population is found to be 15.6
(a) Set up a 99% confidence interval estimate of the true population average amount of paint included in a five-litre can. (Use the z-table.) (b) Based on the results of (a), do you think that the store owner has a right to complain to the manufact..
Based on p=.60, probability that a randomly selected homeowners will say no to newspaper subscription.
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