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A company produces bolts for large-scale construction projects. The shear strength, X, of the bolts is assumed to be a normally distributed variable with a mean strength u=500kg and a standard deviation 10kg. That is, X~N(500, 10). (a) Of all bolts that are produced by this company, what percentage will have strength between 475kg and 520kg.
A Russian SVR agent has 45 million dollars which he can spend to bribe academics, politicians, and bloggers to spread disinformation and to promote anti-American propaganda
A simple random sample of 30 repairs made by this company is taken. The sample average is $97, and the SD is $17. Assume that the repair cost has a normal curve.
Create the 90% confidence interval for mean score of all such subjects. You may suppose scores are usually distributed.
During the development of the Chapin test, it was given to several different groups of people. Do these data support the contention that female and male students differ in average social insight at significance level = 0.1?
suppose that a basketball player can score on a particular shot with probality .3. use the central limit theorem to
Syracuse Roadbuilding Company is considering the purchase of a new tandem box dump truck. The truck costs $95,000, and an additional $5,000 is needed to paint it with the firm logo and install radio equipment.
You are a manager with Appetizer. The company owns a chain of restaurants in the United States. Appetizer is looking for an opportunity to expand.
In 2001, an estimated 78% of executives believed that age bias was a serious problem. In a 2004, 82% of the executives surveyed considered age bias a serious problem.
what is an example of a variable for which we would use a x2
The probability that a call-centre consultant receives 3 calls during any given hour is 0.1404 and the probability that the consultant receives 5 calls during any given hour is 0.1755. Assuming that the calls are Poisson-distributed, calculate the p..
Linear Optimization
In 1851 there were 25,466 nurses in Great Britain. Find the probability that a British nurse selected at random in 1851 would be 60 years or older. (My guess is The sum of the percent of nurses 60 years are older are added equaling 36% or 1967.76/2..
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