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A certain metal oxide has the formula MO where M denotes the metal. A 36.46g sample of the compound is strongly heated in an atmosphere of hydrogen to remove oxygen as water molecules. at the end, 31.70g of the metal are left over. if O has an atomic mass of 16.00 amu, calulate the atomic mass of M and identify the element.
If you take a 67.5 mL portion of 1.98 M. NH3 stock solution and dilute it to a total volume of 0.600 L, what will the concentration of the final solution be?
The standard molar enthalpy change for this reaction is -1.3MJ. What is the enthalpy change when 6 moles of octane are combusted?
After equilibrium is reached, (X)=.55 M. Calculate the Keq (Kc) for this reaction. show full steps please for rating
If 145 grams of potassium nitrate were added to water to make 1,500 mL of solution, what would be the molarity of the resulting solution?
A gaseous mixture of O2 and N2 contains 30.8% nitrogen by mass. What is the partial pressure of oxygen in the mixture if the total pressure is 505mmHg ?
Calculate the energy released when a 28.9 gram piece of copper is cooled from its melting point of 1083 degrees C to 25.0 degrees C. The specific heat of copper is .385 J/g degrees C.
Calculate the pH of the 0.39M NH3/ 0.73M NH4CL buffer system . B) what is the pH after the addition of 20.0 mL of 0.075M NaOH
calculate the values of ?Ho, ?So, and ?Go for the reaction at a pressure of 1 atm and temperature of 298.15 K. C(graphite) + H2O(g) = CO(g) + H2(g)
Draw all the alkenyl side products that could be formed by dehydration of 2-methyl-2-butanol by e1 mechanism
Calculate the pH of each of the following solutions. (a) 0.500 M HONH2 (Kb = 1.1 10-8) (b) 0.500 M HONH3Cl
Titration of the lead and zinc in this aliquot required 34.06 mL of the EDTA solution. Finally, cyanide was used to mask the copper and the zinc in a 25.00 mL aliquot. Titration of the lead required 26.68 mL of the EDTA solution. Determine the com..
After simple distillation, could GC have been used to determine purity of the distillate (final compound). If so, briefly and completely explain
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