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Write a Haskell program that calculates a balanced partition of N items where each item has a value between 0 and K such that the difference between the sum of the values of first partition, S1, and the sum of the values of the second partiton, S2, is minimised. Each partition does not have to have the same number of elements.One classical way to solve this is to use dynamic programming. For dynamic programming to be efficient you should avoid recalculating intermediate results. This can be tricky in a functional language as it does not store state information. The solution is data memoisation. Intermediate results are stored is a data structure when they are initially calculated and then simply retrived when needed.Here is an example of data memoisation in calculating a Fibonacci number.
import Data.Arrayfibonacci :: Integer -> Integerfibonacci n = memo!nwhere memo = array (0, n) [ (i, fib i) | i <- [0..n] ] fib 0 = 0 fib 1 = 1 fib i = memo!(i-1) + memo!(i-2)
This example uses the Array module. Since Haskell is a lazy programming language it only calculates a function when it is needed.
Implement a solution to the balanced partition in Haskell.
#include stdio.h #include math.h float discharge(float,float); void main() { char prompt; float time,out,cr; cr = 100e-6; for (time = 0;time { /* call th
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