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Webcam Driver static library or DLL required for Windows
I want a .dll or .lib file using which i will take a snapshot from the webcam and it can't turn on the webcam LED while taking the snapshot. The library should return the snapshot taken. First, i want it done for 1 brand of webcam. If done, properly, i will need it for many other brands then.
I want to call functions from this library in a C++ program. So, make it allowing for that in mind.
Skills required are C Programming, C++ Programming, Delphi, Windows Desktop, x64/x86 Assembler
Byteland county is very famous for luminous jewels. Luminous jewels are used in making beautiful necklaces. A necklace consists of various luminous jewels of particular colour. Nec
I have a program for school and I am not understanding why one of the variables gets skipped or the arithmetic operators aren''t having any effect as I have tryed defining it sever
In rPeANUt implement the "char getchar()" and "void printstring(char *str)" functions. Using these functions implement the following: void main() { while (1) { ch
differentiate between inbuilt and user defined functions
Write a Program to illustrate the Call by Reference? Here is an illustration: #include . int compute_sum(int *n); int main( void) { int n=3, sum; printf("%d\n",n); /
Verifone pos offline mod vx670 Project Description: I want a programmer who will build custom application for Offline VX670 to collect and save info+pin 1) Press the am
Please give me a programming code of first & follow with c or c++ laqnguage .When anyone give me the programming code of first & follow please explain every lines with the help
Mixed Mode Expressions and Implicit type Conversions A mixed mode expression is one in which the operands are not of the similar type. In this case, the operands are converted
Using a Friend Using a friend function is quite easy. The following example explains a friend function to access members of two classes. class Bclass;
a padovan string p(n) for a natural number n is defined as p(0)=''x'' p(1)=''y'' p(2)=''z'' p(n)=p(n-2)+p(n-3),n>2
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