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Actually these problems are variants of the Distance/Rate problems which we just got done working. The standard equation which will be required for these problems is,
As you can see this formula is extremely similar to the formula we used above.
can you explain -12x-133= 67 - 2x
4+3/5
2=5C
-1 1/2+ v = -3 3/10
the kinetic energy of an object varies directly as the square of its velocity. A certain object traveling at 80 feet per second has a kinetic enrgy of 240 foot-pounds. what would b
#2t+rh=2
x= sum of 2 perfect cubes in two ways
1. f(x)=-2x+7x^2
a+2+3(2a-1)
Sketch the graph parabolas. f (x ) = 2 ( x + 3) 2 - 8 Solution In all of these we will just go through the procedure given above to determine the required points and t
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