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Q. Suppose the probability of David coming to a party is 75% and the probability of Jason coming to a party is 85%. What is the probability that they will both come to a party, assuming the events are independent?
Since the events are independent, we know thatP(David and Jason) = P(David) x P(Jason) = 0.75 x 0.85 = 0.64.There is a 64% probability that both David and Jason will come to a party.
Example: The 15 labeled pool balls are put into a large bin. One ball is selected at random and put back into the box, and then another ball is chosen at random. What is the probability that the black 8 ball is selected both times?
Solution: Since the first ball is replaced before the second is chosen, both picks are independent of each other. Thus P(8 on first) and P(8 on second) are independent.
what is equizilent to 2/5
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