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In chemistry, a steady state is a state in which all state variables are constant in spite of ongoing processes that strive to change them. For an entire system to be at steady state, i.e. for all state variables of a system to be constant, there must be a flow by the system (compare mass balance). One of the easiest examples of such a system is the case of a bathtub with the tap open but without the bottom plug: after a certain time the water flows in and out at the similar rate, so the water level (the state variable being Volume) stabilizes and the system is at steady state.
which of the following is not a characteristic of plunck''s quantum theory of radiation? A) Radiation are associated with energy B) A body can emit less or more than a quantum of e
Describe the following giving suitable examples: i. Cannizzaro reaction ii. Aldol condensation b. Give a chemical test to distinguish among ethanal and propanal.
what is infiltration
Physical properties of monohydric alcohols (a) Character - Monohydric Alcohols are neutral component. These comprise no effect on litmus paper. This is analytical investigation
describe vesper theory?
Define Interfacial potential differences? What is the source of an open-circuit, zero-current cell potential? When no electric current passes through the cell, the electric pot
WHAT IS MEANT BY QUANTUM?
Benzene- Hydrocarbon Benzene is the first or initial member of arenes. It was first revealed by Faraday in year 1825 from whale oil. Mitscherllich (1833) acquired it by distill
please provide tests in a tabular form
Uses of Dihydric Alcohols
Many reactions which seem to be quite easy are indeed very difficult. Thereactions proceed in different steps. In such stepwise difficult reactions, the overall reaction rate is determined by the slowest step between different steps.Several intermediate or unstable species are produced in different steps. Therefore, anstablereaction involving many steps will lead to complex equations. In order to expressthe overall rate of a complex reaction in terms of the individual rate constants, aspecial treatment is required.
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