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Consider the following pseudo-code segment.
1. input y {y is a three-digit hexadecimal number}
2. d ← 0
3. for i = 1 to 3 3.1. char ← ith character from y reading from right to left
3.2. if char = 'A or B or C or D or E or F'
3.2.1. Convert char to its decimal equivalent
3.3. end if
3.4. d <- d + 16i-14. end for
5. output d (a) Trace the pseudo-code for the input y = A2E
(b) Briefly explain in words what this pseudo-code does, including its purpose. You only need to write two or three short sentences to answer this question.
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Subtraction of 01000-01001 using 2's complement method. Ans. Firstly 1's complement of 01001 is 10110 and 2's complement is 10110+ 1 =10111. Thus 01000 = 01000 - 01001
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