From top of a tower a stone is thrown up and it reaches the ground in time t1. A second stone is thrown down with the same speed and it reaches the ground in t2. A third stone is released from rest and it reaches the ground in time t3 then t3= ?solution)
let the intial speed be ''u'' and height be ''h''.
solve case 1 and case 2 for t1 and t2 (quadratic) .
its very easy quest. we just need to find the values in u,g,and v(final velocity,this is constant for the first two cases)
for first throw.
t1= 2u/g + v-u/g=v+u/g
for second throw.
for third release.