Top of a tower a stone, Physics

From top of a tower a stone is thrown up and it reaches the ground in time t1. A second stone is thrown down with the same speed and it reaches the ground in t2. A third stone is released from rest and it reaches the ground in time t3 then t3= ?


let the intial speed be ''u'' and height be ''h''.







solve case 1 and case 2 for t1 and t2 (quadratic) .


Posted Date: 3/26/2013 12:57:50 AM | Location : United States

its very easy quest. we just need to find the values in u,g,and v(final velocity,this is constant for the first two cases)

for first throw.

t1= 2u/g + v-u/g=v+u/g

for second throw.


for third release.


so t3=(t1-t2)/2g


Posted by | Posted Date: 3/26/2013 12:58:51 AM

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