Sequence of interrupts, Assembly Language

Assignment Help:

As an instance of the normal priority mode, imagine that initially AEOI is equal to 0 and all the ISR and IMR bits are clear. Also consider that, as shown in given figure, requests occur concurrently on IR2 and IR4, then a request arrives at IRI, and finally a request arrives at IR3 and that these are the only requests. First of all, ISR2 will be set and the interrupt routine link with IR2 will begin executing. After this routine resets the IF flag to value 1 and when the IRI request, ISRI will be set and the IRI routine will be executed entirety. Whenever it is executing it should reset the IF bit to value 1 and send the essential command to clear ISRI. Upon the return to the IR2 routine, ISR2 is cleared and then ISR4 is set and its routine is started. While this routine is executing IR3is made. It is acknowledged immediately when the IF is reset to value 1, and ISR3 is set. Then the IR3 routine is started. Before the IR3 routine is ended it should clear ISR3 and set IF. The return is made to the IR4 routine, which should be clear ISR4 before the returning to the IR2 routine. The IR2 routine, that already has cleared the ISR2 bit, would easily return to the interrupted program. (Note that if IF is not reset to the value 1 within the interrupt routine, further then interrupts will not be processed till the routine is completed, for instance, the IRET instruction is encountered.)

Although a 1 s is sent to bit 5 of OCW2 usually causes the highest-priority ISR bit (for instance, the last ISR bit to be set) to be cleared, any ISR bit may be explicitly cleared by sending an the OCW2 with the SL, R and EOI bits set to Oil and putting the number of the bit to be cleared in L2-L0. If is sent to the OCW2, then ISR3 will be cleared.

1169_ocw1.jpg

Additionally to the normal priority mode discussed above, OCW2 may rotate the priority by assigning bottom priority to any one of the IR levels. In this kind of case the other priorities will follow as if the normal ordering had been rotated. i.e.  If the lowest priority is given to IR4, then the order of priorities will be as following:

IR5, IR6, IR7, IR0, IR1, IR2, IR3, IR4

(For instance IR5 is rotated into the top-priority position).  A  rotation  by  one may  be  obtained  by  allowing  the combination  for the R and SL bits be value 10. If the R and SL bit combination is II, then the IR level with the lowest priority is the one indicated by L2-LO. If IR5 currently has top priority and

247_ocw2.jpg

It is sent to the OCW2, then the new priority ordering would be

IR6, IR7, IR0, IR1, IR2, IR3, IR4, IR5

1515_ocw3.jpg

It is sent, the new ordering would be

1965_ocw4.jpg

IR3, IR4, IR5, IR6, IR7, IR0, IR1, IR2

The R and SL bits can also have importance when EOI is equal to 0. In this case R is set 1 and SL is set to value 0 cause automatic rotations when AEOI is equal to 1, and R = SL = 0 turns off this action so that automatic rotations do not take place. R = SL = 1 and EOI is equal to 0 result in the lowest priority being designated by L2-LO without an EOI command being sent. The remaining combination, R = 0 and SL = 1, which causes no action.

In OCW3, SMM (special mask mode) bits and the ESMM (enable special mask mode) can be utilized to negate the priority modes describe above. If a byte is sent to the OCW3 in which both  the ESMM and  the SMM are set to  value 1, then unmasked interrupt requests are processed as they arrive (provided that the processor's IF bit is  value1) and the priority order is avoided. By sending subsequently a byte to the OCW3 in which ESMM is equal to value 1 and SMM is equal to value 0, a switch back to the priority ordering of interrupts might be made. If a byte with the ESMM bit equal to value 0 is sent to the OCW3, then the SMM bit will have no effect and the special mask mode will not be change.

The P (polling) bit is used to place the 8259A in polling mode. This mode assume that the CPU is not accepting interrupts (IF = 0) and it is compulsory for the interrupt requests in the IRR to be polled. When the P bit is  value 1 the next RD signal would cause" the suitable bit in the ISR to be set just as if INTA signal had been received, and it would return to the AL register in the CPU a byte of the form

2077_ocw5.jpg

Where I = 1 show that an interrupt is present and W2, W0, and W1 give the IR level of the highest- priority interrupt. For instance, if P = 1, the priority or daring is

IR3, IR4, IR5, IR6, IR7, IR0, IR1, IR2 there are unmasked interrupts on IRI and IR4, and the instruction

IN         AL, 80H

(Where 0080 is the even address of the 8259A) is executed, then

1024_ocw6.jpg

It is input to the AL register.

When P = 0, the contents of IRR or ISR might be read into the AL by setting RR = 1 and executing the instruction

IN         AL, 80H

If at the same time the IN instruction is executed RIS is equal to 0, then IRR is input; or else, ISR is read. The contents of IMR might always be read, using the of 8259A, for example:- for the address assignment denoted above,

IN         AL, 81H

It would input the contents of IMR to AL.

Because  OCW3 bits (except for ESMM) are utilized to indicate whether or not the 8259A is in special mask mode and which information  is to be put on the data bus during a read instruction, these bits are retained till they are reset by the next output to OCW3. For example, if P = 0= RIS and RR = 1 any read from the even address of the 8259A before a new byte is sent to OCW3 will cause IRR to be read.


Related Discussions:- Sequence of interrupts

Code using hla language, You have been hired by the Elbonian government to ...

You have been hired by the Elbonian government to write an Assembly program to help its workforce determine how much their tax will be. The tax laws in Elbonian are very simple. Th

#largest number, #write a program 8086 to find the largest number

#write a program 8086 to find the largest number

Efficient assembly language program, (1) Write a program that will: (a) dis...

(1) Write a program that will: (a) display "Enter Your Name:" (b) convert the entered name to Capital letters (if small), If any other character is entered, the program wil

Program translation sequence, Program Translation Sequence Developing ...

Program Translation Sequence Developing a software program to accomplish a particular task, the implementer chooses an appropriate language, develops the algorithm (a sequence

Introduction to evaluation, This unit introduces the topic of evaluating in...

This unit introduces the topic of evaluating interactive products. It is a short unit as evaluation is discussed in more detail in Block 4. Its brevity should give you additional t

Program to perform a conversion on characters in a text file, Write an asse...

Write an assembly language program to perform a rot13 1 conversion on characters in a text file.  The program should read charatcers from the input file, perform the rot13 convers

Calculator, how to add 111 and 333 in assembly language

how to add 111 and 333 in assembly language

Modes of 8254-microprocessor, Modes of 8254 :   Mode 0 (Inter...

Modes of 8254 :   Mode 0 (Interrupt on Terminal Count)-GATE which value is 1 enables counting and GATE  which value is 0 disables counting, and GATE put not effect on

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd