A FORCE OF 10I-3J+6K NEWTON ACTS ON A BODY OF 5KG AND IT DISPLACESFROM 6I+5J-3KMETRE TO 10I-2J+7K METRE. THE WORK DONE IS
A)100J
B)O
C)121J
D)NONE

Posted Date: 2/21/2013 3:01:00 AM | Location : USA

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