Rules of logarithms, Mathematics

Rule 1

The logarithm of 1 to any base is 0.


We know that any number raised to zero equals 1. That is, a0 = 1, where "a" takes any value. Therefore, the logarithm of 1 to the base a is zero. Mathematically, we express this as loga1 = 0.


What is the value of log101.

Needless to say this would be zero.

Rule 2

The logarithm of a number where the number is the same as the base is 1.


We know that any number raised to the power of 1 is itself. That is a1 = a. Therefore, the logarithm of  a to the base a is equal to 1.

Mathematically, we express this as logaa = 1.


What is the value of log1313?

By applying the above rule, the value of log1313 is 1.

Rule 3

The logarithm of a product to base a is equal to sum of the logarithms of the individual numbers which constitute the product to the same base a. That is,   logaM.N = logaM + logaN.


If M.N is the product and if ax = M and ay = N, then M.N = ax . ay.

By the law of indices  ax. ay = ax+y. Therefore,

ax+y  = M.N

Then the logarithm of M.N to base a is equal to x + y. Mathematically, it will be

loga M.N = x + y                                                      ......(1)

Now, if we express ax = M and ay = N, in terms of logarithms they will be               loga M = x and loga N = y. Substituting the values of x and y in 1, we have

loga (M.N) = loga M + loga N


What is the value of log333?

We know that 33 can be expressed as the product of 3 and 11. That is,    log3 33 = log3 (3 x 11). Applying the above rule this can be expressed as log3 3 + log3 11. Since log33 is 1, we rewrite it as log3 33 = 1 + log3 11.

Rule 4

The logarithm of a fraction to the base a will be equal to the difference of the logarithm of the numerator to the base a and the logarithm of the denominator to base a. That is, loga (M/N) = loga M - loga N.


Let ax = M and ay = N. Then M/N = ax/ay. By the law of indices, this will equal to ax-y. The logarithm of M/N to base 'a' will, therefore, be x - y. Mathematically this is expressed as

      loga (M/N) = x - y .......(1)

If we express ax = M and ay = N in terms of logarithms, they will be loga M = x and loga N = y. Substituting the values of x and y in (1), we have

      loga (M/N) = loga M - loga N


What is the value of log2 (32/4).

By applying the above rule, this can be written as log2 32 - log2 4. This can be further solved. But we look at it only after learning the next rule.

Rule 5

The logarithm of a number raised to any power, integral or fractional, is equal to product of that number and the logarithm of the number raised to base a. That is, loga (MP) = p.logaM.


If M = ax, then loga M = x. Now suppose that M is raised to the power of n, that is Mn. Since M = ax, Mn = anx. This is in accordance with the priniciple that if we perform any operation on an equation it should be performed on both the sides of the equation in order to keep the equation symbol valid.

Mn = anx, if expressed in terms of logarithms will be

      loga(Mn) = nx      ...........(1)

On substituting loga M = x in (1), we have

      loga (Mn) = n . loga M

Similarly if n = 1/r, we have

      loga (M1/r) = (1/r) . loga M

Now we take up the example discussed under Rule 4 and look at how it is further simplified. Before we go on to the next step, let us express log2 32 and log2 4 as log2 25 and log2 22. By rule 5, these are expressed as 5.log22 and 2.log2 2. And since log2 2 is one, 5.log22 and 2.log22 reduce to 5.1 = 5 and 2.1 = 2. Therefore, log2 32 - log24 when simplified gives

  log2(25) - log2(22)

   =   5.log22 - 2.log22

   =   5.1 - 2.1

   =   5 - 2 = 3.

We obtain the same value even by simplifying the term on the left hand side. We know that 32/4 = 8. That is, log28 can be expressed as 23. On application of rule 5, this will be 3.log2 2. Again this gives us 3.1 = 3.

Generally, logarithms are expressed to base 10 and base 'e'. While the logarithms expressed to base 10 are referred to as common logarithms, those expressed to base 'e' are referred to as Napier or Natural logarithms. The value of 'e' is approximately 2.718. In practise common logarithms are expressed as 'log' while natural logarithms are expressed as 'ln'. We want to emphasize that generally the base is not stated and by looking at the manner it is expressed we ought to decide whether it is a common or natural logarithm.

Posted Date: 9/13/2012 5:40:39 AM | Location : United States

Related Discussions:- Rules of logarithms, Assignment Help, Ask Question on Rules of logarithms, Get Answer, Expert's Help, Rules of logarithms Discussions

Write discussion on Rules of logarithms
Your posts are moderated
Related Questions
Write down two more reasons why children consider 'division' difficult. Regarding the first reason given above, one of fie few division related experiences that the child perhaps d

Simpson's Rule - Approximating Definite Integrals This is the last method we're going to take a look at and in this case we will once again divide up the interval [a, b] int

What inequalities and intervals are? If it is given that a real number 'p' is not less than another real number 'q', we understand that either p should be equal to q or

Q. How to Convert Decimals to Percentages? Ans. Remember that when you have a decimal number, the digits to the right of the decimal point have the following meaning:

Verify the Parseval theorem for the discrete-time signal x(n) and its DFT from given equations. Compute the linear convolution of the discrete-time signal x(n) ={3, 2, 2,1} and

A valid identifier in the programming language FORTAN contains a string of one to six alphanumeric characters (the 36 characters A, B,...., Z, 0, 1,...9) starting with a letter. De

The probability that a person will get an electric contract is 2/5 and the contract that he will not get plumbing  contract is 4/7.If the probability of getting at least one contra

Do you subtract when you add integers.

what is the advantage of dual linear problem programming when we maximize profit then what is need to minimize cost of the same problem

Let Consider R A Χ B, S B Χ C be two relations. Then compositions of the relations S and R given by SoR A Χ C and is explained by (a, c) €(S o R) iff € b € B like (a, b) € R,