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RICS/CISC Architecture
An essential aspect of computer architecture is the design of the instruction set for the processor. The instruction set selected for a specific computer determine the way that machine language programs are constructed. Early computers had simple and small instruction sets, forced basically by the have to minimize the hardware used to implement them. With the advent of integrated circuits as digital hardware became cheaper and computer instructions tend to increase both in complexity and number. Many computers contain instruction sets that include more than hundred and sometimes even more than 200 instructions. These computers also employ a variety of data types and a large number of addressing modes. The trend for computer hardware complexity was influenced by several factors, such as upgrading existing models to provide more customer applications, adding instructions that facilitate the translation from high-level language into machine language programs and striving to develop machines that move functions from implementation of software into hardware . A computer with number of instructions is classified as a Complex Instruction Set Computer and abbreviated CISC.
In the early 1980s, a number of computer designers recommended that computers use fewer instructions with easy constructs so they may be executed much faster within the CPU without having to use memory as frequently. This type of computer is classified as a Reduced Instruction Set Computer or RISC.
For an 8088 the 2 addresses linked with an 8259A are normally consecutive, and the AO line is associated to the AO pin, but because there are just 8 data pins on the 8259A and the
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Hand shaking : Handshaking, or 2-way handshaking, is 1 type of strobe operation. It typically involves 2 handshaking lines: an output line to denote when the board is ready an
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how to transfer the data from the file to an array
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Control Transfer or Branching Instruction Control transfer instructions transfer the flow of execution of the program to a new address specified in the instruction indirectly o
Example : Add the contents of the 2000H: 0500H memory location to contents of 3000H: 0600H and store the result in 5000H: 0700H. Solution : Unlike the past example progra
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