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RICS/CISC Architecture
An essential aspect of computer architecture is the design of the instruction set for the processor. The instruction set selected for a specific computer determine the way that machine language programs are constructed. Early computers had simple and small instruction sets, forced basically by the have to minimize the hardware used to implement them. With the advent of integrated circuits as digital hardware became cheaper and computer instructions tend to increase both in complexity and number. Many computers contain instruction sets that include more than hundred and sometimes even more than 200 instructions. These computers also employ a variety of data types and a large number of addressing modes. The trend for computer hardware complexity was influenced by several factors, such as upgrading existing models to provide more customer applications, adding instructions that facilitate the translation from high-level language into machine language programs and striving to develop machines that move functions from implementation of software into hardware . A computer with number of instructions is classified as a Complex Instruction Set Computer and abbreviated CISC.
In the early 1980s, a number of computer designers recommended that computers use fewer instructions with easy constructs so they may be executed much faster within the CPU without having to use memory as frequently. This type of computer is classified as a Reduced Instruction Set Computer or RISC.
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#question. counters using 8051.
Write a procedure to read a text file and copy its contents to another text file using 8086 assembly language .
Addressing mode of 8086 : Addressing mode specify a way of locating operands or data. Depending on the data types used the memory addressing modes and in the instruction ,
MyLocation SDWORD 14 TheTest SDWORD 8 mov eax,MyLocation mov ebx,TheTest neg eax,ebx sub eax,ebx Show exactly what lives in eax after executi
DIV: Unsigned Division:- This instruction performs unsigned division operation. It divides an unsigned word or double word by a 16-bit or 8-bit operand. The dividend might be in t
For an 8088 the 2 addresses linked with an 8259A are normally consecutive, and the AO line is associated to the AO pin, but because there are just 8 data pins on the 8259A and the
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from pin description it seems that 8086 has 16 address/data lines i.e.AD0_AD15.The physical address is however is larger than 2^16.How this condition can be handled
Example : Add the contents of the 2000H: 0500H memory location to contents of 3000H: 0600H and store the result in 5000H: 0700H. Solution : Unlike the past example progra
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