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Program : A program to move a string of the data words from offset 2000H to offset 3000H the length of the string is OFH.
Solution :
For writing this program, we will use an significant facility, available in the 8086 instruction set, for example move string byte/word instruction. We will also study the flexibility imparted by this instructions to the 8086 assembly language program. First write the Program for 8085, supposing that the string is available at location 2000H and is to be moved at 3000 H.
Now consider DS is suitably set, write the sequence for 8086. At first by using the index registers, the program may be written as given.
BY Comparing the above listings for 8085 and 8086 we can conclude that every instruction in 8085 listing is replaced by an alike instruction of 8086. The above 8086 listing is completely correct but it is not competent. Let us try to write the listings for the similar purpose by using the string instruction. Due to the assembler directives and the syntax, one may sense that the program is lengthy, though it eliminates 4 instructions for a MOVSW instruction.
Interrupt System Based on Single 8259 A The 8259A is contained in a 28-pin dual-in-line package that need only a + 5-V supply voltage. Its organization is shown in given figur
The modes are determined by the contents of the control register, whose format is given in Figure These modes are: Mode 0: If a group is in mode 0, it is divided into 2 sets.
ADD: Add :- This instruction adds an immediate contents of a memory location specified in the a register ( source ) or instruction to the contents of another register (destinat
#question. counters using 8051.
Intel's 8237 DMA controller : 1) The 8237 contain 4 independent I/O channels 2) It contains 27 registers, 7 of which are system-wide registers and 5 for each channel. 3)
what is the hex value in ax after executing the instructions ax= 1E8A bx=4080 add al,bl sub ah,bh
I am running a small minecraft server off of my old mac mini, and am having a big issue. My computer isn''t very good, and even just running this server is an issue. I use a comma
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CMP: Compare: - This instruction compares the source operand, which can be a register or memory location an immediate data with a destination operand that might be a register or a
Assume that the registers are initialized to EAX=12345h,EBX =9528h ECX=1275h,EDX=3001h sub AH,AH sub DH,DH mov DL,AL mov CL,3 shl DX,CL shl AX,1 add DX,AX
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