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Example
Multiply 3x5 + 4x3 + 2x - 1 and x4 + 2x2 + 4.
The product is given by
3x5 . (x4 + 2x2 + 4) + 4x3. (x4 + 2x2 + 4) + 2x .
(x4 + 2x2 + 4) - 1 . (x4 + 2x2 + 4)
= 3x5 . x4 + 3x5 . 2x2 + 3x5 . 4 + 4x3 . x4 + 4x3 .
2x2 + 4x3 . 4 + 2x . x4 + 2x . 2x2 + 2x . 4 - x4 - 2x2 - 4
To simplify the above we employ a rule which we will learn in laws of indices. It states that xm . xn = xm+n
= 3x9 + 6x7 + 12x5 + 4x7 + 8x5 + 16x3 + 2x5 + 4x3 + 8x - x4 - 2x2 - 4
Now we collect like terms and simplify them. We obtain 3x9 + 10x7 + 22x5 - x4 + 20x3 - 2x2 + 8x - 4.
Let u = sin(x). Then du = cos(x) dx. So you can now antidifferentiate e^u du. This is e^u + C = e^sin(x) + C. Then substitute your range 0 to pi. e^sin (pi)-e^sin(0) =0-0 =0
Probability - Applications of integrals In this final application of integrals that we'll be looking at we are going to look at probability. Previous to actually getting into
Q) In a lottery ,a person chooses six different natural numbers at random 1to 20,and if there six numbers match with the six numbers already fixed by the lottery committee ,he win
Each Child Is Unique : Although every child goes through similar stages of development, the process may vary from one set of children to another, and also from one child to anoth
what are your 9 times tables
Solve by factorization X 2 +(a/a+b + a+b/a)x+1 = 0 X 2 +(a/a+b + a+b/a)x+1 => X 2 +(a/a+b x a+b/ax + a/a+b .a+b/a) => X[x+a/a+b] +a+b/a[a+a*a+b]= 0 => X= -a
? (2x+3)dx
An unbiased die is tossed twice .Find the probability of getting a 4,5,6 on the first toss and a 1,2,3,4 on the second toss
4/(x+7)(x+4)
help me with how to write sample of proportion using visual basic
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