The value of y that minimizes the sum of the two distances from (3,5) to (1,y) and from (1,y) to (4,9) can be written as a/b where a and b are coprime positive integers. Find a+b.
Solution) The minimum distance of the points from (1,y) is the distance from the intersection of their perpendicular bisectors to the line x=1hence slope of perpendicular bisector=> -4=2y-14 / 2x -7 => 8x + 2y = 42.
putting x=1,y=17, hence a+b= 17 +1 =18 (ANS).