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Interrupt
When the CPU detects an interrupt signal, it stops activity of current and jumps to a special routine, known an interrupt handler. This handler then detects why the interrupt occurred and takes the suitable action. When the handler is over executing this action, it jumps back to the interrupted procedure.
Various levels or "types" of interrupts are supported, from 0 to 255 range. Each type has a booked memory location, known an interrupt vector. The interrupt vector points to the suitable interrupt handler. When 2 or more interrupts occur at the same time, the CPU utilize a priority system The 256 priority levels supported by the Intel 8086-processors may be split into 3 categories:
III rd Generation Microprocessor: The single 3rd generation microprocessor chip having 64-pins began with the introduction of 16-bit Intel 8086 in 1978. The other essential
You are to create an assembly program for the MSP430 that correctly measures the wind direction, to a precision of 45° (N, NW, W, SW, S, SE, E, NE), using the MSP430's ADC. Your
MOVSW/MOVSB : Move String Word or String Byte: Imagine a string of bytes, stored in a set of consecutive memory locations is to be moved to another set of the destination locati
AND: Logical AND: This instruction bit by bit ANDs the source operand that might be an immediate, or a memory location or register to the destination operand that might be a memor
ROL : Rotate Left without Carry: This instruction rotates the content of the destination operand to the left by the specified count bit-wise excluding the carry. The most signific
Internal Architecture of Microprocessor : The architecture of 8086 provides a number of improvements over 8085 architecture. It supports a, a set of 16-bit registers ,16-bit AL
Interrupt System Based on Multiple 8259As A multiple 8259A interrupt system is diagrammed in given figure in this figure data bus drivers are not indicated, but they could be i
Hello
SHORT : The SHORT operator denoted to the assembler that only one byte is needed to code the displacement for a jump (for example displacement is within -128 to +127 bytes fr
You have to write a subroutine (assembly language code using NASM) for the following equation. Dx= ax2+(ax-1)+2*(ax+2)/2
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