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In the array implementation of lists, elements are stored into continuous locations. In order to add an element into the list at the end, we can insert it without any problem. But, assume if we desire to add the element at the starting or middle of the list, then we ought to rewrite all the elements after the position where the element ought to be added. We ought to shift (n)th element to (n+1)th position, where 'n' refer to number of elements in the list. The (n-1)thelement to (n)th position and it will continue till the ( r ) thelement to ( r + 1 )th position, where 'r' refer to the position of insertion. For doing this, thecount will be incremented.
From the above instance, if we desire to add element '35' after element '33'. We ought to shift 77 to the 8th position, 66 to the 7th position, so on, 44 to the 5th position.
Before Insertion
Count 1 2 3 4 5 6 7
11
22
33
44
55
66
77
Step 1
Count 1 2 3 4 5 6 7 8
Step 2
Step 3
Step 4
Step 5
35
Q. Explain that how do we implement two stacks in one array A[1..n] in such a way that neither the stack overflows unless the total number of elements in both stacks together is n.
I=PR/12 numbers of years : Interest Rate up to 1 years : 5.50 Up to 5 years : 6.50 More than 5 year : 6.75 please design an algorithm based on the above information
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