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IMUL: Signed Multiplication: This instruction multiplies a signed byte by a signed bit in source operand e in the register AL or signed word in source operand by signed word in the register AX. The source can be a general purpose register, index register, memory operand or base register, but it can't be an immediate data. In the case of 32- bits results, the higher order word (MSW) is stored in the DX and the lower order word is stored in the register AX. The PF, AF, ZF, and PF flags are undefined after IMUL. If AH and DX both contain parts of 16 and 32-bit result respectively, CF and OF both will be set. The AL and AX are the implicit operands in case of 8 bits and 16 bits multiplications respectively. Sign bit and CF fills the unused higher bits of the result, the AF are cleared. The example instructions are given as follows:
Example :
1. IMUL BH
2. IMUL CX
3. IMUL [SI]
III rd Generation Microprocessor: The single 3rd generation microprocessor chip having 64-pins began with the introduction of 16-bit Intel 8086 in 1978. The other essential
I need to estimate the value of a definite integral using Riemann Sums and For our estimation let f(x) = x2 ,a=0, b=10 and n=5. Where a is the lower bound, b is the upper bound and
CALL : Unconditional Call:- This instruction is utilized to call a subroutine from a basic program. In case of assembly language programming, the term procedure is utilized int
Mov ax, [1234h: 4336h + 100]
As an instance of the normal priority mode, imagine that initially AEOI is equal to 0 and all the ISR and IMR bits are clear. Also consider that, as shown in given figure, requests
Internal Hardware-Interrupts Internal hardware-interrupts are the outcome of sure situations that occur during the execution of a program, for example. Divide by 0. The interru
Ask 2. Exchange higher byte of AX and higher byte of BX registers by using memory location 0160 in between the transfer. Then stores AX and BX registers onto memory location 0174 o
SBB: Subtract with Borrow :- The subtract with borrow instruction subtracts the source operand and the borrow flag (CF) which might reflect the result of the past calculations,
what is implied addressing
calculate the number of one bits in bx and complement an equal number of least significant bits in ax hint use the xor instruction
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