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In the last subsection, we have implemented a stack by using an array. While a stack is implemented by using arrays, it suffers from the basic restriction of an array - i.e., its size cannot be increased or decreased once it is declared. Consequently, one ends up reserving either too much space or too less space for an array and in turn for a stack. This difficulty can be conquering if we implement a stack using a linked list. In the case of a linked stack, we will push and pop nodes from one end of any linked list.
The stack, as linked list is represented as a singly linked list. In the linked list each node contains the data & a pointer which gives location of the next node in the list. Program 2 implements a stack by using linked lists.
How sparse matrix stored in the memory of a computer?
Optimal solution to the problem given below. Obtain the initial solution by VAM Ware houses Stores Availibility I II III IV A 5 1 3 3 34 B 3 3 5 4 15 C 6 4 4 3 12 D 4 –1 4 2 19 Re
Q. Explain w hat are the stacks? How can we use the stacks to check whether an expression is correctly parentheses or not. For example (()) is well formed but (() or )()( is not w
The operations of the Symbol ADT The operations of the Symbol ADT are the following. a==b-returns true if and only if symbols a and bare identical. a symbol bin Unico
sample infosys campusconnect questions
Q. In the given figure find the shortest path from A to Z using Dijkstra's Algorithm. Ans: 1. P=φ; T={A,B,C,D,E,F,G,H,I,J,K,L,M,Z} Let L(A)
The algorithm to delete any node having key from a binary search tree is not simple where as several cases has to be considered. If the node to be deleted contains no sons,
Write c++ function to traverse the threaded binary tree in inorder traversal
Threaded Binary Tree : If a node in a binary tree is not having left or right child or it is a leaf node then that absence of child node is shown by the null pointers. The spac
Q. Write down a non recursive algorithm to traverse a binary tree in order. Ans: N on - recursive algorithm to traverse a binary tree in inorder is as
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