How to calculate coupling factor?, Mechanical Engineering

Q. Two coils with self inductances 1H and 4H have a mutual inductance of 1H. The RMS value of current flowing in the two coils is 4A and 1A respectively. Find the coupling factor




                  Mutual inductance M = 1H


                       L1 = 1 H


                       L2 = 4 H

Given     I1 = 4 Amp


                      I2 = 1 Amp

 The total magnetic energy stored


                W = 1/2L1I12 + 1/2L2I22 ±1/2MI1I2


                W = {1/2 ×1 × 16 } + {1/2 × 4 × 1}± {1/2 × 1 × 4 × 1}


                W = 12 or 8 watt

Posted Date: 7/23/2012 1:09:37 AM | Location : United States

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