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How many lines of address bus must be used to access 2048 bytes of memory when available RAM chips 128 × 8. How many lines of these will be common to each chip?
Ans. AS chips available here of 128 x 8 in size. Thuis means that total 128(27) locations are here and all locations can store 8 bits. Hence the total number of address lines required to access128 locations is 7. Since seven address lines can address 27 locations so all seven lines are common to all chips.
Differentiate the latch and flip-flop? The major difference between latch and FF is which latches is level sensitive whereas FF is edge sensitive. They both need the use of clo
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